5^(4x+3)/25^(9-x)=5^(2x+5)

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Solution for 5^(4x+3)/25^(9-x)=5^(2x+5) equation: 



5^(4x+3)/25^(9-x)=5^(2x+5)

We move all terms to the left:

5^(4x+3)/25^(9-x)-(5^(2x+5))=0



Domain of the equation: 25^(9-x)!=0

x∈R



We add all the numbers together, and all the variables

5^(4x+3)/25^(-1x+9)-(5^(2x+5))=0

We multiply all the terms by the denominator


5^(4x+3)-((5^(2x+5)))*25^(-1x+9)=0



We calculate terms in parentheses: -((5^(2x+5)))*25^(-1x+9), so:

(5^(2x+5)))*25^(-1x+9

We add all the numbers together, and all the variables

-1x+(5^(2x+5)))*25^(+9

Back to the equation:

-(-1x+(5^(2x+5)))*25^(+9)



We add all the numbers together, and all the variables

5^(4x+3)-(-1x+(5^(2x+5)))*25^9=0

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